Answer:
A) attached file
B) attached file
C) attached file
D) Kirchhoff’s junction rule states that at any junction, the sum of the altimeter attained moving into and out of that junction are equal.
While
Kirchhoff’s loop rule states that the algebraic sum of the number of lifts used in any closed loop is equal to zero
Explanation:
Given that the lifts are analogous to batteries, and the runs are analogous to resistors.
So from all the figures. The resistors represent the runs while the lift represents the battery.
Kirchhoff’s junction rule states that at any junction, the sum of the altimeter attained moving into and out of that junction are equal.
While
Kirchhoff’s loop rule states that the algebraic sum of the number of lifts used in any closed loop is equal to zero
Please find the attached file for the sketch
Light travels in waves, and light travels at about 3.0x10^8 m/s. and you call that this the 'speed of light' so your answer possible could be
A. It travels at the speed of light.
I might be wrong so double check.
Answer:
La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.
Explanation:
Potencia es la velocidad o rapidez con la que se consume la energía. Siendo la energía la capacidad que tiene un mecanismo o dispositivo eléctrico cualquiera para realizar un trabajo, también se puede definir potencia como la energía desarrollada o consumida en una unidad de tiempo. Su unidad de medida es el Watt.
La ley de Watt establece que la potencia eléctrica P suministrada por un elemento de circuito, es directamente proporcional al producto entre la tensión de la alimentación V del circuito y la intensidad de corriente I que circula por él.
Matemáticamente, la ley de Watt se expresa:
P = V.I
donde V es medida en Volt e I es medida en Ampere.
En este caso:
Reemplazando:
P= 220 volt* 0.45 ampere
P= 99 Watts
<u><em>La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.</em></u>
Answer:
We conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
Explanation:
Given
To determine
We need to find the quantity of the charge that flows through the wire in 50 s.
Important Tip:
A current of 1 Ampere = 1 Coulomb of charge flowing in 1 second
Using the formula involving charge and current
where:
represents the current in amperes (A)
represents the charge in coulomb (C)
represents the time in seconds (s)
now substituting I = 0.9 and t = 50 in the formula
switch sides
Multiply both sides by 50
Simplify
C
Therefore, we conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
