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3 years ago

How long does it take for an airplane to change its velocity from 140 m/s to 180 m/s if its

Physics

1 answer:

kobusy [5.1K]3 years ago

4 0

Answer:

Explanation:

a = 4ms⁻², Vf = 180 m/s & Vi = 140m/s

a = $\frac{Vf-Vi}{t}$

4 = $\frac{180-140}{t}$

t = 40/4

t = 10sec

To Measure Distance Use third Equation of Motion:

2aS = Vf²-Vi²

S = $\frac{180*180 - 140*140}{2(4)}$

S = 12800/8 = 1600m

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A negative ion of charge -2e is located at the origin and a second negative ion of charge -3e is located nearby at x = 3.8 nm ,

Rus_ich [418]

Answer:

$\vec{F}_{21}=-5.63\times 10^{-11}N\\\\\vec{F}_{21}=\\$

Explanation:

Given that

$Q_1 = -2e\, C\\\\Q_2=-3e\,C\\\\x= 3.8 \times 10^{-9}\,m\\\\y= 3.2 \times 10^{-9}\,m\\\\r=\sqrt{x^2+y^2}\\\\r= 4.96\times 10^{-9} m\\$

As both charges are negative so there exist force of repulsion in direction as shown in figure.

$F_{12}=\frac{kQ_1Q_2}{r^2}\\\\F_{12}= \frac{(9\times 10^9)(6)(1.602\times 10^{-19})^2}{(4.96\times 10^{-9})^2}\\\\F_{12}=5.63\times 10^{-11}N$

Angle at which force F12 is acting is

$\theta=tan^{-1}\frac{3.2}{3.8}\\\\\theta=tan^{-1}\frac{y}{x}\\\\\theta= 40.1^o$

$F_{x}=F_{12}cos\theta\\\\F_{x}=(5.63\times 10^{-11})cos(40.1)\\\\F_{x}=4.306\times 10^{-11}N\\\\F_{y}=F_{12}sin\theta\\\\F_{y}=(5.63\times 10^{-11})sin(40.1)\\\\F_{y}=3.62\times 10^{-11}N\\\\$

$\vec{F}_{12}=\vec{F}_{x}+\vec{F}_y\\\\\vec{F}_{12}=4.30\times 10^{-11}\,\hat{i} + 3.62\times 10^{-11}\,\hat{j}\\\\\vec{F}_{12}=$

Force exerted on charge -2e is equal in magnitude to F12 but is in opposite direction

$F_{21}=-5.63\times 10^{-11}N$

$\vec{F}_{21}=$

7 0

3 years ago

How hot is the sun in degrees Celsius?

Vlada [557]

Answer:

The temperature of the mantle varies greatly, from 1000° Celsius near its boundary with the crust, to 3700° Celsius

hope this helps you!

8 0

3 years ago

A substance has a mass of 2795 g and a volume of 312 cm

denis23 [38]

Answer:

if you are asking for density its 48g/cm^3

Explanation:

3 0

3 years ago

To make the next delivery, Sam-I-Am goes 45 mi/h for 2 hours. How far did he travel in that time?

andrezito [222]

Hello =D

This problem is about cinematic

V = 45 mi/h

t = 2 h

Then

V= X/t

X = V*t

Then

X = (45)*(2)

X = 90 mi

Best regards

5 0

3 years ago

A manometer is used to measure the air pressure in a tank. The fluid used has a specific gravity of 1.25, and the differential h

Sloan [31]

Answer:

77.88 lbm/ft³

Explanation:

Given,

Specific gravity, SG = 1.25

Density of water, ρ = 62.30 lbm/ft³

density of the fluid =

= S.G x ρ_{water}

= 62.30 x 1.25

= 77.88 lbm/ft³

Density of the fluid is equal to 77.88 lbm/ft³

3 0

3 years ago