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algol [13]
3 years ago
9

What did you learn from organize Notes, write 2 to 3 paragraphs explaining how that process is designed to help with your learni

ng process for your classes.
Study Skills Please
Physics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

yo ni siquiera he leido Organizar Notes y quisiera responderte pero el sistema no me deja escribir bien se esta alocando

Explanation:

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Which statement correctly describes the current in a circuit that is made up of any two resistors connected in parallel with a b
AysviL [449]
B is the answer I think
8 0
3 years ago
A jetliner flies at a constant speed covering 467 miles in 3.3 hours. What is the speed of the plane in miles per hour?
stellarik [79]

Answer:

141.152 miles per hour  is the speed of the plane in miles per hour

Explanation:

Speed of plane = Total distance travelled/total time taken -

v = D/t

Substituting the given values in the above equation, we get

v = 467/3.3 miles /hour

v = 141.152 miles per hour

141.152 miles per hour  is the speed of the plane in miles per hour

8 0
3 years ago
The efficiency of a device such as a lamp can be calculated using this equation:
loris [4]

efficiency = (useful energy transferred ÷ energy supplied) × 100

It's easy to use this formula, but we have to know both the useful energy and the energy supplied.  The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out.  I see two ways to do it:

<u>Way #1:</u>

We all know about the law of conservation of energy.  So we know that the total energy coming out must be  250J, because that's how much energy is going in.  The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.

(useful energy) / (energy supplied) =  (175J) / (250J) = <em>70% efficiency</em>

================================

<u>Way #2: </u>

How much of the energy is wasted ? . . . 75J wasted

What percentage of the Input is that 75J ? . . . 75/250 = 30% wasted

30% of the input energy is wasted.  That leaves the other <em>70%</em> to be useful energy.

6 0
3 years ago
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