Answer:
oytqlrvlh<u>q</u><u>x</u><u>t</u><u>q</u><u>l</u><u>x</u><u>p</u><u>l</u><u>y</u><u>m</u><u>p</u><u>x</u><u>m</u><u>h</u><u>m</u><u>r</u>
Applying log rules leaves us with the following equation:
x^2 + 8 = 6x
Change to standard form and solve using factoring.
x^2 - 6x + 8 = 0
(x - 4)(x - 2) = 0
x = 4
x = 2
Hope this helps!
Answer:
function is f(x) = x+6
and the missing outputs are 19, 24 and 27
Answer:
No, the graph fails the vertical line test
Step-by-step explanation:
To determine if the graph is a function, we can use the vertical line test.
Use a vertical line, if the vertical passes through two or more points, the graph is not a function
Looking at the y axis ( which is a vertical line), it passes through two points
This means the graph is not a function
No, the graph fails the vertical line test