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Leviafan [203]
3 years ago
7

Given the side lengths, determine whether thr triangle is acute, right, ovtuse, or not a triangle:

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

1) If sum of the two smaller sides of a triangle is greater than the third longer side, then its a triangle.

<h3>In our case, 20 + 23 > 41. Hence its a triangle .</h3>

Use the side lengths to classify the triangle as acute, right, or obtuse. Compare the square of the length of the longest side with the sum of the squares of the lengths of the two shorter sides

2) Square root of sum of the squares of the two smaller sides is equal to the third longer side, then its a right triangle.

In our case,

√20^2+23^2≈30.4795<41.

<h3>Hence not a right triangle.</h3>

Since the sum of the squares of the two shorter sides is < the square of the longer side, its an obtuse angle triange

Step-by-step explanation:

Hope it is helpful....

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antiseptic1488 [7]

Answer: -8/11 or -.72727...

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3 years ago
Question 3(Multiple Choice Worth 3 points) (07.04) Ashley solved the exponential equation 3x+1 = 15 and her work is shown below.
Mademuasel [1]
She was not supposed to "undistribute" and separate 3x+1 she was supposed to subtract 1 from both sides

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Read 2 more answers
a product code consists of picking a two-digit number (including 00) and 3 not necessarily distinct letters. How many codes are
Brrunno [24]

Answer:

The codes are:

N,_,_,_

Where each _ represents a possible letter, out of 26.

And N is a number of two digits.

So in total we can think that we have 5 empty slots.

_,_,_,_,_

In the first slot we can put any digit between 0 and 9, so here we have 10 options.

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The total number of different combinations is equal to the product of the number of options for each slot.

C = 10*10*26*26*26 = 1,757,600

Now, if we want to have at least one nine, we can fix it in the first slot.

Then we have:

in the first slot we have only one option (the 9)

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The number of combinations is:

C = 1*10*26*26*26 = 175,760

But we also should consider the case where we fix the 9 in the second slot, so the actual number of combinations is twice the number above.

C = 2*175,760 = 351,520

The probability that the code does not contain the number 9.

Now in the first slot we have only 9 options, all the whole numbers between 0 and 8.

The same for the second slot, 9 options.

For the third, fourth and fifth slot is the same as before.

The total number of combinations is:

C = 9*9*26*26*26 = 1,423,656

4 0
3 years ago
Which choice is equivalent to the quotient below?<br> -/100/-/25
alexandr1967 [171]

the answer to this equation is 4

8 0
2 years ago
How many area codes (abc) would be possible if all three digits could be any vaiue 1-9
kifflom [539]

Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

3 0
3 years ago
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