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iVinArrow [24]
3 years ago
12

(Plz answer this)

Chemistry
2 answers:
motikmotik3 years ago
7 0

<span><span>NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution           = 22.4 mlNumber of HCl moles              = (2mol/1000 ml)*22.4 ml                                            =  0.0448 mol</span></span>
Helen [10]3 years ago
6 0
NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution           = 22.4 mlNumber of HCl moles              = (2mol/1000 ml)*22.4 ml                                            =  0.0448 mol
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Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. If 70.8 g of c
Rus_ich [418]

Answer:

1.18 moles of CS₂ are produced by the reaction.

Explanation:

We present the reaction:

5C + 2SO₂  →  CS₂  +  4CO

5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.

As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles

8 0
3 years ago
The phase of matter can be changed by:
stiks02 [169]

Answer: A

Explanation: Mass and volume is the amount, amount doesn’t make the phase of a matter change.

3 0
3 years ago
Read 2 more answers
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

Therefore, the molarity of solution will be 5.2\times 10^{-3}mole/L

MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

Thus the molarity of Cl^- anions in the chemist's solution is 0.0104 M

6 0
3 years ago
A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?
Blizzard [7]

molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)

molar mass = 84.01 g/mol

//

(508g)(1 mol/84.01 g) = 6.0

There are 6.0 moles of sodium bicarbonate

3 0
3 years ago
Complete the following reaction :<br><br>HC≡CH + HBr→? ​
Morgarella [4.7K]

hope it helps you .............

3 0
2 years ago
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