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nata0808 [166]
3 years ago
15

How many different ways can you arrange the letters i, d, t, and e

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

8

Step-by-step explanation:

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Help asap pls 15 points
Alinara [238K]

Answer:

1. 20 by 6

2. 20 by 8

3. 6 by 10

4. 6 by 40

Step-by-step explanation:

just do 2/3 of each number then that is the new number.

1/3 of 30 is 10, so 2/3 is 20.

and so on

4 0
2 years ago
If x = 5, find the value of (x+3)²​
asambeis [7]

Step-by-step explanation:

Given

if x = 5 Then

(x+ 3)²

= ( 5 + 3) ²

= 8²

= 64

Hope it will help :)❤

7 0
2 years ago
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A farmer wants to estimate the average growth in height of his corn plants over a two week period
Cloud [144]

Answer:How much does he usually grow ?

Step-by-step explanation:

8 0
3 years ago
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0
3 years ago
b. What would be the new account balance in five years at a 5.12% if the interest was compounded monthly?
Korolek [52]

Answer: The account will earn in one year the amount of $10,512,000

Step-by-step explanation:

3 0
3 years ago
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