Answer:
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Explanation:
silver(I) iodide + sodium sulfide ⟶ silver(I) sulfide + sodium iodide
1. Convert the word equation to a chemical equation:
AgI + Na₂S ⟶ Ag₂S + NaI
2. Put a 1 in front of the most complicated-looking formula (Na₂S?):
AgI + <u>1</u>Na₂S ⟶ Ag₂S + NaI
3. Balance Na:
We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaI.
AgI + <u>1</u>Na₂S ⟶ Ag₂S +<u>2</u>NaI
4. Balance S:
We have fixed 1 S on the left. We need 1 O on the right. Put a 1 in front of Ag₂S.
AgI + 1Na₂S ⟶ 1Ag₂S +2NaI
5. Balance Ag:
We have fixed 2Ag on the right. We need 2 Ag on the left. Put a 2 in front of AgI.
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Every formula now has a coefficient. The equation should be balanced.
6. Check that atoms balance:
<u>Atom</u> <u>On the left</u> <u>On the right
</u>
Ag 2 2
I 2 2
Na 2 2
S 1 1
The balanced equation is
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
0.25 g al should equal around 0.009265594867125 moles
I hope this help
Answer:
None
Explanation:
Cl₂ is above Br₂ in the activity series.
Bromine will not displace chlorine from its salts.
The reaction will not occur.
Volume of NaOH required to react = 145.5 ml
<h3>Further explanation</h3>
Reaction
CO₂(g)
+ 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)
The volume of CO₂ : 0.45 L
mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

Then volume of NaOH :

Answer is B- F has a smaller radius than F− because an additional electron causes greater repulsion in F− is the correct choice and the nuclear charge the radius of the anion increases.
Explanation: I hoped that helped!