1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lukranit [14]
3 years ago
14

Answer the question please

Chemistry
1 answer:
emmainna [20.7K]3 years ago
3 0
It’s 190 calories without milk
You might be interested in
The value of ΔH° for the reaction below is -6535 kJ. ________ kJ of heat are released in the combustion of 16.0 g of C6H6 (l)?
Umnica [9.8K]

Answer:

the value of H° is below -6535 kj. +6H2O

Explanation:

6H2O answer solved

3 0
3 years ago
C12H26O + SO3+NaOH ----> C12H25NaSO4+ H2O
Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

4 0
3 years ago
Explain the difference between an endothermic and an exothermic reaction using the concepts of potential energy, stability, and
kakasveta [241]
An Exothermic reaction releases energy into the surroundings and so the products have more potential energy then the reactants. The enthalpy change is a negative value. Whereas, an endothermic reaction involves the absorption of energy into the system and so the reactants have more potential energy than the products. The enthalpy change is a positive value. This is clearly represented in energy profile diagrams.
4 0
3 years ago
How to do 22.4 kg/L to kg/mL
emmainna [20.7K]
1 kg/L ----------- 0.001 kg/mL
22.4 kg/L ------- ??

22.4 x 0.001 / 1 => 0.0224 kg/mL
6 0
3 years ago
An important industrial route to extremely pure acetic acid is the reaction of methanol with carbon monoxide:
Nastasia [14]

The reaction has had a heat that is enthalpy of -22 kJ/mol. The exothermic process has been signaled by the negative sign.

The amount of energy that the system absorbs or releases to create the products is described as the heat of reaction.

The source of the reaction's heat is

H is equal to 3(413 Kj/mol) + 358 Kj/mol + 467 Kj/mol + 1070 Kj/mol = 3134 Kj/mol.

H prod equals 3(413 kj/mol) plus 347 kj/mol plus 358 kj/mol plus 467 kj/mol plus 745 kj/mol, or 3156 kj/mol.

H=3134 kj/mol - 3156 kj/mol = -22 Kj/mol

Negative findings point to an exothermic response.

A chemical process known as an exothermic reaction releases energy in the form of heat or light.

Learn more about exothermic reaction here-

brainly.com/question/10373907

#SPJ4

7 0
1 year ago
Other questions:
  • How does the modern periodic table arrange elements?
    7·1 answer
  • Which statement describes potential energy? A. energy of motion B. stored energy C. energy due to heat D. used energy
    12·2 answers
  • How many grams of hydrogen are contained in 2.00 mol of C6H7N
    9·1 answer
  • 1. The Russian chemist who designed the first accepted version of periodic table in the 1800s was ______________.
    7·1 answer
  • Why can't helium bond with hydrogen?
    13·1 answer
  • The product of electron capture decay of argon isotope 37ar is
    8·1 answer
  • Beta particles will: 1. bend toward the North Pole of a magnet. 2 bend toward the South Pole of the magnet 3 not be affected by
    10·2 answers
  • Yyh5hththththtnthhrr​
    12·2 answers
  • Determine y for the following equation: log(9/8)=y
    6·1 answer
  • Calculate the how many sodium atoms must react completely to give 33,6 dm³ hydro-
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!