What is the product of (3a+2)(16a-2a+9)

Mathematics

1 answer:

-BARSIC- [3]4 years ago

5 0

Answer:

42a^2 + 55a + 18

Step-by-step explanation:

The product is a factorization. I multipled like terms togethers to recieve the answer. I hope this helps you. Please mark brainliest if it is correct, thanks.

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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48

andrezito [222]

Answer:

$y=0.2x+284$

Step-by-step explanation:

Let x be the distance driven, d-distance and C our constant.

Our information can be presented as:

$y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2$

#Subtracting equation 2 from 1:

$70=350x\\x=0.2$

Hence the fixed cost per mile driven, $x$ is $0.20

To find the constant, $C$ we substitute $x$ in any of the equations:

$450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284$

Now, substituting our values in the linear equation:

$y=0.2x+284$ #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

7 0

3 years ago

90units needed 8 units per case what's the #of cases & # of additional units

Kobotan [32]

Answer:

# of cases: 11

Additional units: 2

Step-by-step explanation:

If each case can hold 8 units, and we want to find the total # number of cases, we have to divide the # of units (8) for one case by the total # units (90).

As you can see, after dividing by 8, we have a total of 11 cases and a remainder of 2 units. The remainder will be the # of additional units because we cannot have another case filled with 8 units.