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Paul [167]
3 years ago
8

Is

is what" alt="the square root of 196 is what" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Find the square root of a number is basically finding a perfect square. For example, the square root of 25 is 5 because when 5 is squared, you get 25.

√196 = 14

14^2 = 196

Best of Luck!

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Find the solution of the system of equations.<br> -x+3y=9<br> -x-y=-3
Inessa [10]

Step-by-step explanation:

use the steps of simultaneous

elimination steps

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3 years ago
What’s the answer need help ?
Zielflug [23.3K]

Answer:

B

Step-by-step explanation:

Just move point D over 6 and down 10

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3 years ago
Can someone explain how to do this, please?​
BartSMP [9]

Answer:

\sqrt{ {28x}^{2} - 6x }

Step-by-step explanation:

You would substitute "2x" for every "x" in the function in the same way you would substitute any other number.

So if f(x)=Sqrt[7x²-3x], then: f(2x)=Sqrt[7(2x)²-3(2x)]

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6 0
3 years ago
Chris and John are buying the same car, a 2014 Nissan Maxima. Chris is financially responsible, has a great credit score, a 3% i
AleksAgata [21]
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3 0
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Show that 3x^2 -2x + 1 is always greater than 0.<br> ( This is an Additional Math Question )
Leviafan [203]

Answer:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

Step-by-step explanation:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)

Consider x^2-2/3x+1/3

Remember that (a-b)^2 =a^2-2ab+b^2

x^2=a^2

a=x

-2/3x= -2*x*b

b=1/3

S0 (x-1/3)^2= x^2-2/3x+1/9

x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

6 0
3 years ago
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