Step-by-step explanation:
use the steps of simultaneous
elimination steps
Answer:
B
Step-by-step explanation:
Just move point D over 6 and down 10
Answer:

Step-by-step explanation:
You would substitute "2x" for every "x" in the function in the same way you would substitute any other number.
So if f(x)=Sqrt[7x²-3x], then: f(2x)=Sqrt[7(2x)²-3(2x)]
=Sqrt[7(4x²)-3(2x)]
=Sqrt[28x²-6x]
Total amount paid by Chris = 4000 + (22500 - 4000)(1 + 0.03)^5 = 4000 + 18500(1.03)^5 = 4000 + 21446.57 = $25446.57
Total amount paid by John = 5000 + (22500 - 5000)(1 + 0.12)^5 = 5000 + 17500(1.12)^5 = 5000 + 30840.98 = $35,840.98
John paid $10,394.41 more than Chris.
Answer:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
Step-by-step explanation:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)
Consider x^2-2/3x+1/3
Remember that (a-b)^2 =a^2-2ab+b^2
x^2=a^2
a=x
-2/3x= -2*x*b
b=1/3
S0 (x-1/3)^2= x^2-2/3x+1/9
x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved