Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
i believe you have to divide 8 by each number to get the distance between the pairs of integers.
Step-by-step explanation:
Answer:
x^12 y^2 z^11
a= 12
b= 2
c= 11
Step-by-step explanation:
On the numerator you distribute the exponent 3 to the other exponents.
I think you multiply the 3 so you would get: x^15 y^3 z^12.
so it looks like x^15 y^3 z^12 / x^3yz
Then you subtract the top exponents from the bottom exponent because when you are dividing you subtract exponents. the exponent for y and z in the denominator is 1
and thats how i got x^12 y^2 and z^11. The exponents are a b and c
I hope that is right
<span>Ray
Q is the ray that angle PQR and SQR shares. Because both angles has the ray of
Q.
ray refers to a line with one endpoint
P is a ray, Q is a ray, R is a ray and S is a ray. When you put them together,
they form angle.
Pls. see attachment for the presentation of the angle PQR and SQR and how they
share ray Q</span>
$469.
376/4 = 94.
Then add that too 346
94 + 346 = 469
