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olchik [2.2K]
4 years ago
11

Which statement best describes how work and power are different?

Physics
1 answer:
WARRIOR [948]4 years ago
6 0
Hello
the best answer is c
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How to solve god initial speed
CaHeK987 [17]

Answer:

Velocity is a function of time and defined by both a magnitude and a direction. [1] Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question.

This is from a website btw.

4 0
4 years ago
If you push on a wall with a force of 200 N, with what force does the wall push back?
PSYCHO15rus [73]
200 N, that is if the force is balanced and the wall doesn't move
8 0
3 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
What is the molar mass of C8H10N4O2
lesya [120]

Answer:

194,22g/mol

Explanation:

8*12,01+10*1,01+4*14,01+2*16=194,22g/mol

3 0
3 years ago
Read 2 more answers
Energy is always conserved. It cannot be created or destroyed. It can, however, be transferred between objects or systems, from
sweet-ann [11.9K]

Have in mind: Energy is always conserved and, (...) be transferred between objects or systems, from one form to another.

Hence, the true relation is C, when a system gains kinetic energy, it loses potential energy.

Think about this,

K + P = constant

If K increases, then P need to decreases to holds the above relation.

5 0
4 years ago
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