5m/s
Explanation:
Given parameters:
Mass of ball = 0.1kg
Force on the ball = 5N
time taken = 0.1s
Unknown:
final speed of the ball = ?
Solution:
According to newton's second law "the net force on a body is the product of its mass and acceleration".
Force = mass x acceleration equation 1
Acceleration =
V is the final velocity
U is the initial velocity
T is the time taken
U = O since it is a stationary body;
a = 
Input "a" into equation 1
F = m x
5 = 0.1 x 
V = 5m/s
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Hello!
Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.
We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)
- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)
Both of these act in opposite directions. Let's use the equation for torque:
Doing the summation using their respective lever arms:
Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:
Now, let's solve for 'T'.
Plugging in the values:
All of those are true, except the one about the radius.
Both ends of a chord have to be on the circle, but one end
of a radius is at the center, so a radius can't be a chord.
las ondas electromagnéticasSon aquellas ondas que no necesitan un medio material para propagarse. Incluyen, entre otras, la luz visible y las ondas de radio, televisión y telefonía. ... Las ondas electromagnéticas se propagan mediante una oscilación de campos eléctricos y magnéticos.
Answer:
0.22 m
Explanation:
m = 0.43 kg, K = 561 N/m
Vmax = 8 m/s
Let the amplitude of the oscillations be A.
The formula for the angular frequency of oscillation sis given by
ω = 36.1 rad/s
The formula for the maximum velocity is given by
Vmax = ω x A
A = Vmax / ω
A = 8 / 36.1 = 0.22 m
