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liraira [26]
3 years ago
8

In an investigation with density, Marcia’s teacher measures the mass and volume of 10 different samples of a substance. The samp

les are numbered 1 through 10. Then, the teacher makes the graph that is shown below. What is the independent variable in this investigation? mass volume sample number substance density

Chemistry
2 answers:
valina [46]3 years ago
3 0

Answer:

Mass  

Step-by-step explanation:

Usually, you plot the independent variable along the horizontal (x) axis and the dependent variable along the vertical (y) axis.

Marcia's teacher plotted the mass of the sample along the x-axis and volume along the y-axis.

The mass is the independent variable, because that is <em>what the teacher varied</em>.

The volume is the <em>dependent variable</em>, because it <em>depends</em> on the mass.

Sample number is <em>wrong</em>, because it is not a variable.

Substance is <em>wrong</em>, because all samples consist of the same substance.

Density is <em>wrong</em>, because it is constant. It is the slope of the graph.

emmainna [20.7K]3 years ago
3 0

Answer:mass

Explanation:

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jeka94

Answer:

T_f = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

T_i = 21.5°C

C_{calorimeter} = 6.15 kJ/°C

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since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate ×  \frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

=  0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter =  C_{calorimeter} (T_f-T_i} )

21.84 kJ =6.15 kJ/°C * (T_f-21,5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - 132.225 kJ

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154.065 kJ = (6.15 kJ/^0C * T_f)

T_f = \frac{154.065kJ}{6.15kJ/^0C}

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4 0
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6 0
2 years ago
Please only answer if you know the actual thing, don't search it up! Are these correct? :P
makkiz [27]

Hey buddy I am here to help!

1. C

2. A

3. A & B

4. C

5. C

6. A

7. A

8. A & C

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Plz mark brainlist!

4 0
3 years ago
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amid [387]
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A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate
saveliy_v [14]

Answer:

m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

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Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

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Best regards!

4 0
3 years ago
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