Answer:
H3O^+ < HClO2 < H3PO4< HCOOH < H2PO4^-<CIO2^-<H2O< HCOO^-
Explanation:
The pH of a solution refers to the negative logarithm of it's hydrogen ion concentration. Generally, the hydrogen ion concentration of an acid is always greater than that of its conjugate base. Hence, the conjugate acid always has a lower pH than the conjugate base.
This can be seen in the species, H3O^+ and H2O, HClO2 and ClO2^- etc.
Answer:
The sodium nitrate is more economical
Explanation:
Hi, to compare this two options you need to determine the amount of nitrogen per 100 lb of both and then estimate its cost:
1) Sodium nitrate
This fertilizer has 30 % by weight of sodium nitrate:
The molecular weight of sodium nitrate:
So, this salt has 14 g of N per 85 g:
Cost per gram:
2) Ammonium sulfate
This fertilizer has 20 % by weight of ammonium sulfate:
The molecular weight of ammonium sulfate:
So, this salt has 14 g of N per 114 g:
Cost per gram:
Answer:
The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42
Explanation:
Molarity is a unit of concentration based on the volume of a solution and is defined as the number of moles of solute per liter of solution. Then, the molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution.
Molarity is expressed in units ().
Then you must know the amount of moles of the NaCl solute. For that it is necessary to know the molar mass. Being:
-
Na: 23 g/mole
- Cl: 35.45 g/mole
the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole
Then a rule of three applies as follows: if 58.45 grams are present in 1 mole of NaCl, 10 grams in how many moles will they be?
moles= 0.171
So you know:
- number of moles of solute= 0.171 moles
- volume= 50 mL= 0.05 L
Replacing in the definition of molarity:
Solving:
Molarity= 3.42
<u><em>The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 </em></u><u><em></em></u>
Answer:
Universe, galaxy, solar system, star, planet, moon and asteroid.
Explanation:
You're welcome!
it is a <em>Chemical property</em>