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Virty [35]
3 years ago
9

Atoms bond to other atoms through their electrons. The following analogy will be used to help us understand how this occurs. Ima

gine that the atoms of different elements are like kids coming to school. Each of these "kids" come to school with a specific number of crayons. These crayons represent the outer electrons for that atom. Explain how the elements (kids) share, gain, lose their crayons (electrons) and bond to another so that they achieve stability.
Chemistry
1 answer:
horsena [70]3 years ago
4 0

Answer:

Explanation:

All atoms (except for group 0 elements) of elements tend to achieve stability by having there outermost shell completely filled; achieving an octet configuration. During chemical bonding, atoms tend to achieve stability majorly in one of the two ways below

1) Ionic or electrovalent bonding: This involves the transfer of electrons from a positively charged ion (cation) to a negatively charged ion (anion). Here, no molecule is formed. For instance, in the formation of a sodium chloride (NaCl) salt. Sodium ion donates the single electron on it's outermost shell (to achieve it's octet configuration) to chloride ion (which needs just one more electron in it's outermost shell to achieve it's octet configuration).

Na⁺ + Cl⁻ ⇒ NaCl

2) Covalent bond: This involves the sharing of lone pair of electrons between two atoms to form a molecule. For example, the outermost shell of an oxygen atom, has two single electrons (that are not in pair), these single electrons can form covalent bond independently with hydrogen atoms (to form water) that also have just one electron in their shells. Hence, at every "covalent bonding site", an electron from oxygen and an electron of hydrogen is shared between the two atoms in order to achieve a stable configuration (Here, we have two "covalent bonding sites").

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One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
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Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

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V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

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How many moles of LiOH are required to prepare 1.50L of 5.4 M LiOH?
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Among timber, wind, and oil, which is a fossil fuel and which is not?
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A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3
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<em>The mass of a gold bar  = 1.424 x 10⁴ gram</em>

<em></em>

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

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mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

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