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Kitty [74]
3 years ago
13

How to solve this with steps

Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0
I want to answer this, but I can't tell what the picture is. (please take a better photo)
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Please help i need
Anon25 [30]

The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

<h3>what is measure centre and measure of variation? </h3>

A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.

The measure of central tendency includes the mean, median and mode.

The measure of variation describes the amount of variability or spread in a set of data.

The common  measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.

Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

learn more on measure of centre and variation here: brainly.com/question/23769503

#SPJ1

7 0
2 years ago
How do you multiply decimals?
Ulleksa [173]
I found this online, hope it helps


Just follow these steps:
Multiply normally, ignoring the decimal points.
Then put the decimal point in the answer - it will have as many decimal places as the two original numbers combined.
5 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
-45 / -5 = <br> plz can you help me
garri49 [273]
It would be 9 buddy. Negative divided by negative turns into positive. 45 divided by 5 is 9.
5 0
3 years ago
Read 2 more answers
one satellite radio service charges $10 per month plus and activation fee of $20. A second service charges $11 per month plus an
Mamont248 [21]
Y=10x+20
y=11x+15
5 months
8 0
3 years ago
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