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madreJ [45]
4 years ago
13

What would be the resulting molarity of a solution made by dissolving 21.9 grams of KCl in enough water to make an 869-millilite

r solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
viktelen [127]4 years ago
8 0
Molar mass KCl = <span>74.5513 g/mol

Number of moles:

21.9 / 74.5513 => 0.293 moles

Volume = 869 mL / 1000 => 0.869 L

Molarity = moles / Volume

Molarity = 0.293 / 0.869

=> 0.337 M</span>
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A precipitate is a product of a reaction that is insoluble in the reaction medium (usually water).

Why?

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AgNO₃(aq) + NaCl(aq) → AgCl(s)↓ + NaNO₃(aq)

In this reaction, Silver Chloride (AgCl) is an insoluble product of the reaction, and precipitates out of the reaction medium

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If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
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Answer:

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Explanation:

Hello,

In this case, given the balanced reaction:

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Best regards.

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