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4 years ago

11

Which of the following will ammonium ion form an insoluble salt? 4/16 a. chloride b. sulfate c. sulfate and carbonate d. carbona

te e. none of the above

1 answer:

Darina [25.2K]4 years ago

6 0

Answer:

e

Explanation:

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The normal freezing point of cyclohexane is 6.55 C. When 0.458 g of benzophenone is dissolved in 15.0 g of cyclohexane, the free

ella [17]

Answer:

The experimental molar mass of benzophenone is 182 g/m (option A)

Explanation:

ΔT = Kf . m . i

(i means the Van't Hoff factor, since benzophenone is not electrolyte, the value for i is 1)

ΔT = T° - T' (Melting temp sv pure - Melting temp sv in sl)

Kf is data (the cryoscopic constant)

m is molality (moles from solute in 1kg of solvent)

6,55°C - 3,19°C = 20,0° C/m . m

3,36 °C = 20,0 C/m . m

3,36 °C /20,0 m/C = m

0,168 = m

We have 0,168 moles of benzophenone in 1 kg of cyclohexane but we don't have 1kg, we have just 15 g so, we need the rule of three.

1000 g ______ 0,168 moles

15 g ________ (15 g . 0,168 m) / 1000 g = 0,00252 m

Now we can get the molar mass:

0,458 g of benzophenone / 0,00252 moles = 181,7 g/m

3 0

3 years ago

What did we discover with this experiment

riadik2000 [5.3K]

B is the correct answer

5 0

4 years ago

What is the concentration, mass/volume percent (m/v), of a solution prepared from 50.0 g NaCl and 2500 mL of water?

Rzqust [24]

answer: 25.0%

Explanation:

thats the answer

8 0

3 years ago

Calcium Carbonate has solubility product constant (Ksp) of 3.3 x 109

Gelneren [198K]

Answer:

no

Explanation:

bc no shshshhshsdhddhhdhdhdhf

5 0

3 years ago

After two half-lives, how much of the original material has decayed? 25 percent 50 percent 75 percent 100 percent

RideAnS [48]

The original material has decayed 75%

<h3>Further explanation</h3>

Given

two half-life

Required

The decayed sample

Solution

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

t = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

t = 2 x t 1/2

Input the value :

$\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%$

The amount of Nt = 25% No

8 0

3 years ago