Determine the volume in liters occupied by 22.6 g of I2 gas at STP.

Chemistry

1 answer:

AleksandrR [38]3 years ago

6 0

The volume in liters occupied by 22.6 g of I₂ gas at STP is 1.99 L (answer A)

calculation

Step: find the moles of I₂

moles= mass÷ molar mass

from periodic table the molar mass of I₂ is 253.8 g/mol

moles = 22.6 g÷253.8 g/mol =0.089 moles

Step 2:find the volume of I₂ at STP

At STP 1 moles =22.4 L

0.089 moles= ? L

by cross multiplication

={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L

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3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,

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Answer:

$Cp_{liquid}=2.54\frac{J}{g\°C}$

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In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

$Q_{Ag}=-Q_{liquid}$

That in terms of the heat capacities, masses and temperature changes turns out:

$m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})$

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

$Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}$