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Inessa [10]
3 years ago
9

Which pair of ratios is proportional?

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

C. 18/24 and 6/12 is proportional

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Each hat cost $9. Each scarf cost $4 less than each hat. What is the total for 7 hats and 9 scarves? Write a number sentence for
Sladkaya [172]
9xh = total cost of the hat 
9 per hat - 4 = $5 each scarf

h = hat 
s = scarf
(9xh) + (5x s)
(9x7) + (5x9) = 108
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983,576,091 what is the value of the 8
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It's value is 80 million
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Imagine your playing a game, you are currently level 5 and it takes 55 EXP to level up to level 6, each battle you fight you gai
sattari [20]

Step-by-step explanation:

55 / 3 = 18.333.

Since it is a decimal, we round up to the nearest whole number.

It will take at least 19 battles to level up.

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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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3 years ago
Write and graph an equation to represent the situation.
gulaghasi [49]

464 divide by 16 is 29. So y would be 29


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