Answer:
Explanation:
Hello,
In this case, the described chemical reaction is:
Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:
Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:
Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:
Best regards.
Answer:
<u>∆H° reaction = -890.3 kJ</u>
Explanation:
The given equation is :
Now ,
O2 is in the standard state so its ∆H° is zero.
∆H° is calculated by considering the formation of CO2 , H2O and CH4 .
..........∆H°a = -393.5 kJ
.....∆H°b = -285.8 kJ
..........∆H°c = -74.8 kJ
Multiply equation of water H2O by 2
and reverse the direction of equation of CH4
Hence the sign of ∆H°c = +74.8 kJ becomes +ve.
We are doing this because CH4 is to be in the reactant side not in the product side.
∆H° reaction = ∆H°a +2(∆H°b) -∆H°c
∆H° reaction = -393.5 - 2(285.8) + 74.8
∆H° reaction = -890.3 kJ
It is not used up in a reaction. This is because a catalyst is added to a reaction in order to speed it up, but only for that—it doesn’t react with anything, so it isn’t a product nor reactant of any reaction
Answer:
(C) 4-ethyl-2,2-dimethylheptane.
Explanation:
Step one: draw the carbon skeletons of each "IUPAC name" as if they were accurate. Note that
- Hexane: a carbon backbone of six carbon atoms, linked in a row with carbon-carbon single bonds.
- Heptane: a carbon backbone of seven carbon atoms, linked in a row with carbon-carbon single bonds.
- A methyl group is a one-carbon substitute -CH₃ for an H atom on the backbone.
- An ethyl group is a two-carbon substitute -CH₂-CH₃ for an H atom on the backbone.
- A propyl group is a three-carbon substitute -CH₂-CH₂-CH₃ for an H atom on the backbone.
Step two: check the structures and the names against the IUPAC rules.
There are many of these rules. Ones that apply here include:
- The backbone shall be named after the longest chain of carbon atoms. There may be right angles but the chain needs to be continuous.
- List the substitutes in alphabetical order (e.g,, ethyl, methyl, and propyl.)
- Number the substitutes from the end that ensures the smallest number for the first substitute group that is encounter. If starting from both ends lead to the same number for the first group, check the second group.
Refer to the sketch attached.
<h3>(A)</h3>
Should start numbering from the other end.
<h3>(B) and (D)</h3>
The longest backbone contains seven carbon atoms.
Answer:
having a valence of zero.
Explanation:
