Sugar would not increase the boiling point of the water as much as the others.To show this, we recall the equation for boiling point elevation ∆t:
∆t = i Kb m
The difference in these four solutions will be in the product of the van't Hoff Factor i and molality m: i * m.
If we assume that we have 0.1m of each solute, the products i*m for these solutions are:
Solution Identity of particles i i * m
0.1 m NaCl Na+, Cl- 2 2 * 0.1 = 0.2
0.1 m MgSO4 Mg^2+, SO4^2- 2 2 * 0.1 = 0.2
0.1 m K2SO4 two K+, SO4^2- 3 3 * 0.1 = 0.3
0.1 m C12H22O11 covalently bonded molecules 1 1 * 0.1 = 0.1
Therefore, having the lowest i * m, sucrose will have the lowest boiling point elevation.
If i am not mistake u can use -log[concentration of oh-] to find it
ie -log[6.4*10^-10]=9.19
Answer:
The Density of Magnesium.
Explanation:
Answer:
1) Hydrolysis
2)Dehydration
3)Dehydration
4)Hydrolysis
Explanation:
Hydrolysis is the chemical breakdown of substances by water and depends on the chemistry, solubility, pH, and the oxidation–reduction (Eh or redox) potential of compound
<em>https://www.sciencedirect.com/topics/earth-and-planetary-sciences/hydrolysis</em>
With hydrolysis water will be a reactant, not a product, and is associated with breaking down substances. Hence 1 and 4 being a Hydrolysis reaction.
Dehydration on the other hand, is defined as :
In a dehydration reaction, either a hydroxyl group from one molecule combines with a hydrogen atom from the other molecule, or two hydrogen atoms from one molecule combine with an oxygen atom on the other molecule. In either case, water is released, and the two molecules are joined together.
https://www.albert.io/blog/dehydration-synthesis-ap-biology-crash-course/
Therefore it is associated with creating a bond of sorts, and water is a product, which is why 2 and 3 are dehydration.
Hope this helps!
Isn't it a because in b at the start of the equation the E in Fe just disappeared
