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Tatiana [17]
2 years ago
10

David has 4 cages of hamsters. The second cage has 1/2 as many hamsters as the first. The third cage has 1/2 as many hamsters as

the second. The fourth cage has 1/2 as many hamsters as the third. What are the fewest hamsters David can have?
Mathematics
2 answers:
atroni [7]2 years ago
8 0

Answer:

1/4 of the first cage

maria [59]2 years ago
8 0

Answer:

Lets reverse it

The 4th cage can have minimum 1 hamster

The 3rd cage can have minimum 2 hamster

The 2nd cage can have minimum 4 hamster

The 1st cage can have minimum 8 hamster

David has 15hamsters

Brainliest please

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Answer:

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The process would be different if some values are the same values already on the chart total of each class.

ie) 20  31  14  22 20 31

small data like this below you can rearrange

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and see that 21 is the correct value

as there are even numbers, so we choose 20 , 22

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Step-by-step explanation:

If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.

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pshichka [43]

Answer:

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Step-by-step explanation:

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i will use proportions for this.

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Hope it helps. :)

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