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Tatiana [17]
3 years ago
10

David has 4 cages of hamsters. The second cage has 1/2 as many hamsters as the first. The third cage has 1/2 as many hamsters as

the second. The fourth cage has 1/2 as many hamsters as the third. What are the fewest hamsters David can have?
Mathematics
2 answers:
atroni [7]3 years ago
8 0

Answer:

1/4 of the first cage

maria [59]3 years ago
8 0

Answer:

Lets reverse it

The 4th cage can have minimum 1 hamster

The 3rd cage can have minimum 2 hamster

The 2nd cage can have minimum 4 hamster

The 1st cage can have minimum 8 hamster

David has 15hamsters

Brainliest please

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Step-by-step explanation:

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<em>Comment on the squaring</em>

There are several ways you can find the square (x+4)².

  1. Use your knowledge that (x+a)² = x²+2ax+a².
  2. Use FOIL* to compute (x+4)(x+4) = x² +4x +4x +4² = x²+8x+16
  3. Use the distributive property: (x+4)(x+4) = x(x+4) +4(x+4) = x² +4x +4x +4² (same as FOIL for two binomials)

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* FOIL is mnemonic for {First, Outer, Inner, Last} referring to pairs of terms in the factors (x +a)(x +b). The x terms are the First terms. The Outer terms are the first x and b. The Inner terms are "a" and the second x. The Last terms are "a" and "b". You are to form the sum of those pairs of terms to find the product of the binomials.

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