Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
41×16 is 656 because 1×6 is 6. 6×4 is 24. 1×1 is 1. 1×4 is 4. The numbers left are 246 ( 1×6 + 6×4 ), and 41 ( 1×1 + 1×4 ). All together, the answer is 656. Enjoy! :)
This is a problem involving the subtraction of two functions f(x) and g(x):
<span>if f(x)=3x-1 and g(x)=x+2, find (f-g)(x). In other words, find:
</span><span> f(x) = 3x-1
-{g(x) -(x+2)
-----------------
f(x) - g(x) = 3x - 1 - x - 2 = 2x - 3 (answer)</span>
You first have to find the slope using the slope formula. That looks like this with our values:
. So the slope is -1/8. Use one of the points to first write the equation in y = mx + b form. We have an x and a y to use from one of the points and we also have the slope we just found. Filling in accordingly to solve for b gives us
and
. Adding 5/8 to both sides and getting a common denominator gives us that
. Writing our slope-intercept form we have
. Standard form for a line is Ax + By = C...no fractions allowed. So let's get rid of that 8 by multiplying each term by 8 to get 8y = -x - 11. Add x to both sides to get it into the correct form: x + 8y = -11
The equation you provided is an ellipse; when graphed, it will make an oval shape.
