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3 years ago

When a person uses an iron to remove the wrinkles from a shirt why does the heat travel from iron to the shirt?

1 answer:

3 0

it transfers through conduction, the molecules of the iron are bumping into the molecules of the shirt, giving them energy.

Hope this Helped

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A 125 g compound consists of 37% oxygen? What is the mass of oxygen in this compound?

zepelin [54]

19.44%

I think that's the anwer

7 0

3 years ago

When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t

Harlamova29_29 [7]

Answer: Molarity of $MgCl_2$ in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{\text{no of moles}}{\text{Volume in L}}$

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{1.96}{1.00L}$

$Molarity=1.96mol/L$

Thus molarity of $MgCl_2$ in the original sample was 1.96M

4 0

3 years ago

Besides the concentration of the acid and its conjugate base, what else does one need to calculate the ph of a weak acid

Marta_Voda [28]

$K_{a}$ , the acid disassociation constant.

3 0

4 years ago

a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa

lesya692 [45]

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

6 0

3 years ago

Read 2 more answers

Some magnesium powder was mixed with some copper( II)oxide and heated strongly. there was a victorious reaction producing a lot

-BARSIC- [3]

Reaction:

$\mathrm{Mg \: + \: CuO \rightarrow Cu\: + \: MgO}$

Magnesium is a stronger reducing agent than copper and is thus able to reduce copper(II) oxide.

Products of the reaction: Magnesium oxide and metallic copper.

4 0

3 years ago

Read 2 more answers