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7nadin3 [17]
3 years ago
13

How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?

Chemistry
2 answers:
bekas [8.4K]3 years ago
7 0

<u>Answer:</u> The amount of heat required is 8625.4 J

<u>Explanation:</u>

To calculate the heat required, we use the equation:

q=mc\Delta T

where,

q = heat required = ?

m = mass of aluminium = 125 g

c = specific heat capacity of aluminium = 0.902 J/g.°C

\Delta T = change in temperature = T_2-T_1=95.5-19=76.5^oC

Putting values in above equation, we get:

q=125g\times 0.902J/g.^oC\times 76.5^oC\\\\\q=8625.4J

Hence, the amount of heat required is 8625.4 J

Katen [24]3 years ago
3 0
The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J
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\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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