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Klio2033 [76]
3 years ago
11

What specifically determines how much energy is available in a molecule

Chemistry
1 answer:
irina1246 [14]3 years ago
5 0
Possibly the amount of electrons and energy levels in which the electrons reside

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20 points! So I got this lab report to do and I need some more info it's about lab safety got any info I can use! :) If so, Than
FromTheMoon [43]
Don’t eat or drink in labs

Dress for the lab; don’t wear open toed shoes

Dispose of lab waste properly

No horse play

Don’t taste or sniff things in the lab

Tire your hair back
8 0
3 years ago
How Many Hill Tops are shown in the attached Map?​
JulijaS [17]

Answer:

5 mountain

Explanation:

5 0
3 years ago
Read 2 more answers
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
A small piece of Cr metal reacts with dilute HNO3 to form H2 (g), which is collected over water at 18 C in a large flask. The to
Sauron [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The partial pressure is P_p= 737.5 mm \ of  \ Hg

Explanation:

The Partial pressure of H_2 is mathematically represented as

           P_p = P_T -P_w

Where P_T is the total pressure of water with a value of 15.5 mm of Hg

           P_w is the partial pressure of water with a value 753 mm of Hg

Now substituting values

          P_p = 753-15.5

               P_p= 737.5 mm \ of  \ Hg

       

3 0
3 years ago
Read 2 more answers
Determine the formula of chromic acid.
Katyanochek1 [597]

<u>Answer:</u> The formula of chromic acid is H_2CrO_4

<u>Explanation:</u>

We are given an ionic compound named as chromic acid. This acid is formed by the combination of hydrogen ion and chromate ion.

An acid is defined as the substance which releases hydrogen ion when dissolved in water.

Hydrogen is the 1st element of periodic table having electronic configuration of 1s^1.

This element will loose 1 electron to form H^{+} ion.

Chromate ion is a polyatomic ion having chemical formula of CrO_4^{2-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for the given compound is H_2CrO_4

Thus, the formula of chromic acid is H_2CrO_4

8 0
3 years ago
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