Answer:
Option (d) is correct.
(1, 0) is the solution of the given system of equation.
Step-by-step explanation:
Consider the given system of equation
4x - 2y = 4 ........(1)
6x - 4y = 6 ........(2)
We have to solve the system algebraically ,
We will solve it by elimination method,
Multiply equation (1) by 2, we get,
(1) ⇒ 8x - 4y = 8 ............(3)
Subtract equation (2) from (3) , we get,
8x - 4y - (6x - 4y) = 8 - 6
8x - 4y - 6x + 4y = 2
8x - 6x = 2
⇒ x = 1
Substitute x = 1 in (1) and solve for y , we get,
⇒ 4x - 2y = 4 ⇒ 4 (1) - 2y = 4 ⇒ 2y = 4 - 4 ⇒ 2y = 0 ⇒ y = 0
Thus, (1, 0) is the solution of the given system of equation.
Option (d) is correct.
