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Nimfa-mama [501]
3 years ago
13

Can anyone please help me answer this math question right away?

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

 here help u  3/5

Step-by-step explanation:  u want see my work?

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180 red marbles to 145 blue marbles
saul85 [17]

Answer:

325

Step-by-step explanation:

180+145 xDDDD

6 0
3 years ago
X + 4y = -3 x + 7y = - 12 *
Leokris [45]

Answer:

??? Please be specific

Step-by-step explanation:

5 0
4 years ago
An 8-ounce bottle of glue costs $1.92. What is the unit price
lukranit [14]

Answer:

$0.27 for 1 ounce

Step-by-step explanation:

Hope this helps!!!

8 0
4 years ago
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

4 0
4 years ago
Read 2 more answers
Compute the range for a distribution where the highest score is 89 and the lowest score is 27.
amid [387]

Answer:

The range of the distribution is 62

Step-by-step explanation:

Here in this question, we are interested in computing the value for the range.

Mathematically;

range = Highest value - lowest value

from the question, highest valve = 89 while lowest value = 27

Plugging the values into the range equation, we have;

Range = 89-27 = 62

4 0
4 years ago
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