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QveST [7]
3 years ago
6

Please help QUICK WILL MARK BRAINLIEST

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

B. -2.3

Step-by-step explanation:

It looks like the graph goes down about 7, and over 3, so B makes sense.

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Help me with this problem I've been working on it for a while now and just can't figure it out
Serggg [28]
1. Write out the problem: 3x+12/3

2. Find the common factor: 3(x+4)/3

3. Cancel out the threes.

4. Once you cancel them out you get: x+4

Hope I could help. Have a great day!:-)))
7 0
3 years ago
I need help with this any help will be appreciated
Mars2501 [29]
Are you trying to solve for x and y?

y=2x+1; x+2y=17
sub in one variable in the other equation.
x+2(2x+1)=17
x+4x+2=17
5x=15
x=3

now that you have x value, plug into the original equation to find y and check with the other. 
y=2(3)+1 = 7
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7 0
3 years ago
8.0007 * 10 to the 6 power
SVETLANKA909090 [29]

Answer: 8000700

Step-by-step explanation:

10 to the 6th power is 100000

1000000 * 8.0007 = 8000700

4 0
3 years ago
In creating a new scale for the mercury thermometer, anders celsius initially set the boiling point of water at _____. a. 0° b.
anastassius [24]

Answer: 100 °

Step-by-step explanation:

6 0
2 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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