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Anarel [89]
3 years ago
6

How does the momentum of a 75 kilogram stationary football player compare with that of a 70 kilogram player moving at a velocity

of 6 meters/second?
The 70 kilogram player has momentum whereas the 75 kilogram stationary player has none.

The 75 kilogram player has more momentum than the 70 kilogram stationary player.

Both players have the same momentum.

The 75 kilogram player has momentum whereas the 70-kilogram stationary player has none.

Neither player has momentum.

I'm thinking its E... can someone help?
Physics
2 answers:
tester [92]3 years ago
7 0
Momentum = mass * velocity
So for an object to have momentum, it has to be moving. The 75 kg player is not moving, so he has no momentum.

A is the correct choice
Verizon [17]3 years ago
5 0
This question is easier to think about if you ignore all the numbers
and just consider that one man is moving and the other one isn't. 

Momentum is proportional to speed, so the man who's moving
has momentum, and the man who's not moving doesn't have any.
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7 0
3 years ago
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An artificial satellite circles Earth in a circular orbit at a location where the acceleration due to gravity is 9.00 m/s2. Dete
Ksju [112]
 <span>g = GMe/Re^2, where Re = Radius of earth (6360km), G = 6.67x10^-11 Nm^2/kg^2, and Me = Mass of earth. On the earth's surface, g = 9.81 m/s^2, so the radius of your orbit is:


R = Re * sqrt (9.81 m/s^2 / 9.00 m/s^2) = 6640km 

here, the speed of the satellite is:

v = sqrt(R*9.00m/s^2) = 7730 m/s 

  the time it would take the satellite to complete one full rotation is:

T = 2*pi*R/v = 5397 s * 1h/3600s = 1.50 h 

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6 0
3 years ago
Un cuerpo de 60 kg se encuentra a una distancia de 3.5 m del otro cuerpo, de manera que entre ellos se produce una fuerza de 6.5
aev [14]

Answer:

1989.6Kg

Explanation:

The computation of the mass of the other body is given below:

As we know that

F = G × m1 × m2 ÷ r²

Here the G would have the constant value i.e. 6.67 × 10^-11Nm² / kg².  

Now

6.5 × 10^-7N = 6.67 × 10^-11Nm² / kg² × 60Kg × m2 / (3.5m) ²

m2 = (F × r²) / (G × m1)

m2 = (6.5 × 10^-7N × (3.5m) ²) ÷ (6.67 × 10^-11Nm² / kg² × 60Kg)

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7 0
3 years ago
A 74 kg firefighter slides, from rest, 4.9 m down a vertical pole. (a) If the firefighter holds onto the pole lightly, so that t
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Answer:

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\sum\overrightarrow{F}=m\overrightarrow{a} (1)

Here the only force acting on the firefighter is the weight F=mg so (1) is:

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Vf^{2}=2a\varDelta x

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Vf=9.8\frac{m}{s}

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I know this is correct i have done all the research

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