An unknown solid is placed on a triple beam balance and has a mass of 2.5 grams. The solid then displaces 35 ml of water in a gr
aduated cylinder. The substance has a density of
2.5 grams
35 ml
.
Where would you place this property in the Venn diagram?
A) A
B) B
C) C
D) D
2.5 grams
35 ml
.
Where would you place this property in the Venn diagram?
A) A
B) B
C) C
D) D
2 answers:
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Answer:- 14.0 moles of hydrogen present in 2.00 moles of .
Solution:- We have been given with 2.00 moles of and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
Answer:
2.01 M
Explanation:
Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)
The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.
Step 2: Convert the volume of solution to liters
We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)
Step 3: Calculate the molarity of the solution
The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution