Answer:
0.3415 J/g °C
Explanation:
M1 = 213.0g
c1 = ?
T1 = 70.2°C
T3 = 25.6 °C
T2 = 22.5°C
C2 = 4.186 J/g°C
Vol. of water = 250mL = 250cm³
p (density of water ) = 1g/L
p = mass / volume
mass (m) = density (p) * volume (v)
m = 1 * 250 = 250g
Heat loss by metal = heat gain by water
Q1 = Q2
Mc∇T = Mc∇T
Mc (T1 - T3) = Mc* (T3 - T2)
213 * c * (70.2 - 25.6) = 250 * 4.186 * (25.6 - 22.5)
(213 * 44.6)c = 1046.5 * 3.1
9499c = 3244.15
c = 0.3415 J/g.°C
The specific heat capacity of the metal is 0.3415 J/g °C
Answer:
Mass = 0.8 g
Explanation:
Given data:
Mass of oxygen = 3.2 g
Mass of CH₄ = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of O₂:
Number of moles = mass/molar mass
Number of moles = 3.2 g/ 32 g/mol
Number of moles = 0.1 mol
Now we will compare the moles of CH₄ and O₂.
O₂ : CH₄
2 : 1
0.1 : 1/2 = 0.1 = 0.05
Mass of CH₄:
Mass = number of moles × molar mass
Mass = 0.05 mol × 16 g/mol
Mass = 0.8 g
<span>Oxygen-16 atomic number is 8 so it has 8 protons. Its atomic weight is 16 so 16-8 = 8 neutrons.
Hope I helped. :) </span>
Answer:
A
Explanation:
because the species being oxidized shares electrons with the species that is reduced.making the oxidized element positively charged and the reduced element negatively charged.
I hope this helps
Answer:
1.788 C DEGREES
Explanation:
STP is 1 atm at 273.15 K
P1V1/T1 = P2V2/T2
(1)(62.65) / (273.15) = (612/760)(78.31)/T2
T2 = 274.93 K = 1.788 C
