Answer:
The height of the flagpole is 46 feet
Step-by-step explanation:
First we find the ratio to connect the variables
Tan(∅) = opposite/adjacent
Plug in the Variables
Tan(39) = x/50
Solve for x
50*tan(39) = x
x = 40.48
Don't forget to include the man's height
40.48 + 6 = 46.48
- 8x + 44 ≥ 60
- 8x ≥ 60 - 44
- 8x ≥ 16
x ≤ - 2
- 4x + 50 < 58
- 4x < 58 - 50
- 4x < 8
x > - 2
Now put the two together. Logically, these two answers since a number cannot be both less than AND greater than - 2.
Your answer should be no solution.
Answer:
Your answer will be the third function
Step-by-step explanation:
The base function you need to know is h(t)= 1/2at^2
Your acceleration in this problem is going to be gravity which they give to you, 32 feet per second squared. Since the ball is falling, it means it will have negative acceleration. Now you have the equation h(t)= -16t^2. The final step is to add the initial height from which the ball was dropped giving you: h(t)= -16t^2 +12
Step-by-step explanation:
464.5cm³
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