To get the exact measurement
We use the formula:
PV = nRT
First let us get the volume V:
volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3
Convert this to m^3:
volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3
n = PV / RT
n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm /
mol K)
<span>n = 1,978.13 mol</span>
1. 2650000
2. 2410
3. 48100
Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x =
= 8.25 moles