Answer:
-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.
Explanation:
Mass of nitrogen triiodide = 20.0 g
Moles of nitrogen triiodide = 

According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.
Answer:
2.35 M
Explanation:
Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

Then you have to convert mL to L.

Now divide the mol by the L.

Round to the smallest number of significant figures = 2.35M
Answer:
53.6 grams of silver chloride was produced.
Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
Mass of silver nitrate = 50.0 g
Mass of hydrogen chloride = 50.0 g
Mass of silver chloride = x
Mass of nitric acid = 46.4 g
Mass of silver nitrate + Mass of hydrogen chloride =
Mass of silver chloride + Mass of nitric acid
[te]50.0 g+50.0 g=x+46.4 g[/tex]

53.6 grams of silver chloride was produced.
Answer:
Approximately
, assuming that this acid is monoprotic.
Explanation:
Assume that this acid is monoprotic. Let
denote this acid.
.
Initial concentration of
without any dissociation:
.
After
of that was dissociated, the concentration of both
and
(conjugate base of this acid) would become:
.
Concentration of
in the solution after dissociation:
.
Let
,
, and
denote the concentration (in
or
) of the corresponding species at equilibrium. Calculate the acid dissociation constant
for
, under the assumption that this acid is monoprotic:
.