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3 years ago

How many moles and atoms are there in 60 grams of Calcium? quick answer plz i m preparing for exams

Chemistry

1 answer:

Nesterboy [21]3 years ago

4 0

Answer:

the number of mol that 60 gram of calcium will have this 1.5 mol.

as number of mole is equal to

n=w/m which is

60/40 which is 1.5 mol

and that of the number of atoms it will have will be 60 over 40 times the algorithm constant 6.223 times 10 to the power 23 which will give 9.0 345 ×10²³

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When 0.100 mol of carbon is burned in a closed vessel with8.00

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Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of $O_2$ = 8.00 g

Molar mass of $O_2$ = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of $O_2$ .

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{8g}{32g/mole}=0.25moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C+O_2\rightarrow 2CO$

From the balanced reaction we conclude that

As, 2 mole of $C$ react with 1 mole of $O_2$

So, 0.1 moles of $C$ react with $\frac{0.1}{2}=0.05$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO$

From the reaction, we conclude that

As, 2 mole of $C$ react to give 2 mole of $CO$

So, 0.1 moles of $C$ react to give 0.1 moles of $CO$

Now we have to calculate the mass of $CO$

$\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO$

$\text{ Mass of }CO=(0.1moles)\times (28g/mole)=2.8g$

Therefore, the mass of carbon monoxide form can be 2.8 grams.

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3 years ago