Answer:
1.35 g
Explanation:
Data Given:
mass of Potassium Permagnate (KMnO₄) = 3.34 g
Mass of Oxygen: ?
Solution:
First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)
So,
Molar Mass of KMnO₄ = 39 + 55 + 4(16)
Molar Mass of KMnO₄ = 158 g/mol
Calculate the mole percent composition of Oxygen in Potassium Permagnate (KMnO₄).
Mass contributed by Oxygen (O) = 4 (16) = 64 g
Since the percentage of compound is 100
So,
Percent of Oxygen (O) = 64 / 158 x 100
Percent of Oxygen (O) = 40.5 %
It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.
So,
for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be
mass of Oxygen (O) = 0.405 x 3.34 g
mass of Oxygen (O) = 1.35 g
Answer:
See balanced equations below
Explanation:
1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)
This is a single replacement reaction, involving an acid with a metal
2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂
3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)
4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)
B.
1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)
2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction
3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)
4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)
5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl
6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)
Carbon-12 has the following electron configuration: 1s2-2s2-2p2. As seen in the configuration, the right answer is: the first electron shell has 4 orbitals.
Answer:
H₂ (g) + O₂ (g) ⇒ H₂O (g)
Explanation:
Hydrogen and oxygen gas both exist as diatomic molecules. The water is in gaseous state due to the heat given off by the combustion reaction.
Answer:
metallic bonding
because it ids good conductor of electricity
