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3 years ago

How many moles of phosphoric acid can be formed from 3000 g of diphosphorus pentoxide?

Chemistry

1 answer:

Semenov [28]3 years ago

7 0

Answer:

42.2 moles of H3PO4

Explanation:

The equation of the reaction is:

P2O5(s) + 3 H2O(l) ⟶ 2 H3PO4.

First we must obtain the number of moles of P2O5 from

Number of moles of P2O5= reacting mass of P2O5/molar mass of P2O5

Molar mass of P2O5= 141.9445 g/mol

Number of moles= 3000g/141.9445 g/mol = 21.1 moles of P2O5

From the reaction equation;

1 mole of P2O5 yields 2 moles of H3PO4

21.1 moles of P2O5 will yield 21.1 ×2/ 1 = 42.2 moles of H3PO4

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a flas

valentina_108 [34]

Answer:

Kp = 0.022

Explanation:

Full question: ...With 2.3 atm of ammonia gas at 32. °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of hydrogen gas to be 0.69 atm.

The equilibrium of ammonia occurs as follows:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where Kp is defined as:

$Kp = \frac{P_{N_2}P_{H_2}^3}{P_{NH_3}^2}$

Where P represents partial pressure of each gas.

As initial pressure of ammonia is 2.3atm, its equilibrium concentration will be:

P(NH₃) = 2.3atm - 2X

Where X represents reaction coordinate

Thus, pressure of hydrogen and nitrogen is:

P(N₂) = X

P(H₂) = 3X.

As partial pressure of hydrogen is 0.69atm:

3X = 0.69

X = 0.23atm:

P(NH₃) = 2.3atm - 2(0.23atm) = 1.84atm

P(N₂) = 0.23atm

P(H₂) = 0.69atm

$Kp = \frac{0.23atm*0.69atm^3}{1.84atm^2}$

8 0

3 years ago

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of

lianna [129]

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2 (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

8 0

3 years ago

A student needs to prepare 50.0 mL of a 1.20 M aqueous H2O2 solution. Calculate the volume of 4.9 M H2O2 stock solution that sho

Nonamiya [84]

Answer : The volume of 4.9 M $H_2O_2$ stock solution used to prepare the solution is, 12.24 ml

Solution : Given,

Molarity of aqueous $H_2O_2$ solution = 1.20 M = 1.20 mole/L

Volume of aqueous $H_2O_2$ solution = 50.0 ml = 0.05 L

(1 L = 1000 ml)

Molarity of $H_2O_2$ stock solution = 4.9 M = 4.9 mole/L

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1$ = Molarity of aqueous $H_2O_2$ solution

$M_2$ = Molarity of $H_2O_2$ stock solution

$V_1$ = Volume of aqueous $H_2O_2$ solution

$V_2$ = Volume of $H_2O_2$ stock solution

Now put all the given values in this formula, we get the volume of $H_2O_2$ stock solution.

$(1.20mole/L)\times (0.05L)=(4.9mole/L)\times V_2$

By rearranging the term, we get

$V_2=0.01224L=12.24ml$

Therefore, the volume of 4.9 M $H_2O_2$ stock solution used to prepare the solution is, 12.24 ml

3 0

3 years ago

What type of substances make better conductors

baherus [9]

I'm pretty sure its metals that make good conductors.

5 0

3 years ago

If a 2.50 liter container is filled with Ne gas at a pressure of 650 mm Hg and at 25°C, what mass of Ne is in the container?

seraphim [82]

Answer:

1.76 g is the mass of Ne is in the container.

Explanation:

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 650 mm Hg

V = Volume of the gas = 2.50 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of Ne gas = ?

Putting values in above equation, we get:

$650mmHg\times 2.50L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{650\times 2.50}{62.3637\times 298}=0.0874mol$

Also, molar mass of Ne = 20.1797 g/mol

So, $Mass = Moles\times Molar\ mass = 0.0874\times 20.1797 g = 1.76\ g$

1.76 g is the mass of Ne is in the container.

7 0

3 years ago