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Leviafan [203]
3 years ago
15

How many moles of phosphoric acid can be formed from 3000 g of diphosphorus pentoxide?

Chemistry
1 answer:
Semenov [28]3 years ago
7 0

Answer:

42.2 moles of H3PO4

Explanation:

The equation of the reaction is:

P2O5(s) + 3 H2O(l) ⟶ 2 H3PO4.

First we must obtain the number of moles of P2O5 from

Number of moles of P2O5= reacting mass of P2O5/molar mass of P2O5

Molar mass of P2O5= 141.9445 g/mol

Number of moles= 3000g/141.9445 g/mol = 21.1 moles of P2O5

From the reaction equation;

1 mole of P2O5 yields 2 moles of H3PO4

21.1 moles of P2O5 will yield 21.1 ×2/ 1 = 42.2 moles of H3PO4

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7 0
3 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

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Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
3 years ago
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