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kirill115 [55]
3 years ago
6

I NEED HELP I don’t understand

Mathematics
2 answers:
Luden [163]3 years ago
5 0
False true true false
kotegsom [21]3 years ago
3 0

Answer:

Step-by-step explanation:

Whole numbers are numbers such as 0, 1, 2, 3, 4. Irrational numbers are numbers that cannot be represented as a ratio, such as \sqrt{2}. The first one would be false.

Rational numbers are numbers that can be represented as a ratio, like \frac{4}{5} or \frac{2}{1}. Because 4/5 is not a whole number but is a rational number, the second one would be true.

Irrational numbers are numbers that cannot be represented as a ratio. Because integers can be represented as a ratio, since integers are numbers like -2, -1, 0, 1, 2, etc, all irrational numbers are not integers and, therefore, the third one is false.

Using the definition of rational numbers and integers from responses two and three, respectively, this fourth one is false.  

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What are the solutions of 3x2 + 14x + 16 = 0?
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Good evening ,

Answer:

x = StartFraction negative 8 Over 3 EndFraction, –2

Step-by-step explanation:

3x² + 14x + 16 = 0

3x² + 6x + 8x + 16 = 0

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3 years ago
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The complete question in the attached figure

we know that

sin40° = opposite side / hypotenuse
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AC=10*sin 40

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3 years ago
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Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
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Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

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This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

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r = \frac{\ln{1.79}}{8}

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Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
4 years ago
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Answer:

c

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