[-4(-2)-8]+[-1-(-2)^3]+2(-2)^3
(8-8)+(-1+8)-64
7-64
57
N-the number
the product of 8 and the number: 8 × n = 8n
5 less than the 8n: <u>8n - 5</u>
We have the triangle 30° - 60° - 90°.
The lenght of the sides are in proportion: 

Answer:
84.3%
Step-by-step explanation:
You first find the frequency. You do this by multiplying the frequency density by the class length.
Answer:
197,8879 N.
Step-by-step explanation:
The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.
The question given says that Nancy is pushing the statue with a force of 120 N at a 60° angle to the horizontal and Harry is pulling the statue with a force of 180 N at a 40° angle with the horizontal.
With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.
The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.
F= (120 N cos 60°) + (180 N x cos 40°)
F= 197,8879 N