$\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
\\\\\\
c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
\\\\\\
c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
\\\\\\
c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2$

7 0

3 years ago

Dennis is going to use a number line to multiply 6 × 4.

Sergeeva-Olga [200]

B. The answer will always be to the right of 4.
6 x 4 = 24
24 is greater than 4, which means it is to the right of 4. On a number line, numbers increase from left to right.

8 0

2 years ago

Read 2 more answers

2/3÷ 1/2 = 2/3 x 2/1 =​

2/3÷ 1/2 = 2/3 x 2/1 =