Question

Can someone help me with this?

Answer 1

Answer:

Energy of a single photon with the given wavelength is $E=3.32\times 10^{-19}\ J$

Explanation:

It is given that,  

The wavelength of yellow light,  $\lambda=6\times 10^{-7}\ m$

The equation that gives the relationship between the energy and the frequency of the wave is called Plank's equation. Mathematically, it can be written as :

$E=h\nu$

where $\nu$ is the frequency of the wave and $\nu=\dfrac{c}{\lambda}$

h is Planck's constant

So, $E=\dfrac{hc}{\lambda}$

$E=\dfrac{6.62\times 10^{-34}\ J-s\times 3\times 10^8\ m/s}{6\times 10^{-7}\ m}$

$E=3.32\times 10^{-19}\ J$

So, the energy of photon is $E=3.32\times 10^{-19}\ J$