An object travels in a straight line, then comes to rest
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Calculate the 2 horizontal and verticle vectors of the velocity 78 m/s
the horizontal vector is what we want becoz the verticle vector is goin to be 0 at the max height.
the horizontal vector if 7.8Cos(17) = 7.46 m/s
So, now we have the velocity and we already have the mass, we can calculate KE,
.5(m)(v)^2
= 5779.8 J
I hope my answer is right, if not just comment, i will help u
:)
You can tell the difference between two peoples voices while they say the same word by the pitch of their voice
Answer:
3.69 N
Explanation:
Draw a free body diagram. There are four forces acting on the object:
Weight force W pulling straight down.
Normal force N pushing perpendicular to the inclined plane.
Friction force f pushing down the inclined plane.
Applied force P pushing up the inclined plane.
Sum of forces in the perpendicular direction:
∑F = ma
N − W cos θ = 0
N = W cos θ
Friction force is normal force times the coefficient of friction:
f = Nμ
f = Wμ cos θ
Plug in values:
f = (15.0 N) (0.300) cos 35.0°
f = 3.69 N