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Inga [223]
3 years ago
5

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by lamar's worm?

Physics
1 answer:
kumpel [21]3 years ago
6 0

Complete question is;

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by Lamar’s work?

A) The elastic potential energy is the same for any distance from a reference point.

B) The gravitational potential energy equals the work needed to lift the object.

C) The gravitational potential energy is the same for any distance from a reference point.

D) The elastic potential energy equals the work needed to stretch the object

Answer:

B) The gravitational potential energy equals the work needed to lift the object.

Explanation:

In physics, we know that potential energy is the energy of a body at rest while the energy of a body in motion is known as kinetic energy.

However,the work required to lift a body from it's position of rest is equal to the Gravitational potential energy of that body.

Elastic potential energy is the one that is stored as a result of force applied to deform an elastic object. Thus, it is not equal to the work needed to stretch the object and it is also not the same for any distance from reference point.

Thus, looking at the options, Option B is correct

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3 years ago
A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

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Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

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               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

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A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10×104 m/s2 , and 1.85 ms (1 ms = 10−3
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Answer:

u = - 38.85 m/s^-1

Explanation:

given data:

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