Answer:
K = 0.045 J
Explanation:
It is given that,
Mass of a ball, m = 10 g = 0.01 kg
Speed of the ball, v = 3 m/s
To find,
The energy of the ball.
Solution,
Due to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :
So, the ball will have a kinetic energy of 0.045 J.
This question involves the concepts of density, volume, and mass.
The approximate diameter of a magnesium atom is "3.55 x 10⁻¹⁰ m".
<h3>STEP 1 (FINDING MASS OF INDIVIDUAL ATOM)</h3>It is given that:
Mass of one mole = 24 grams
Mass of 6 x 10²³ atoms = 24 grams
Mass of 1 atom = = 4 x 10⁻²³ grams
where,
Therefore,
V = 2.35 x 10⁻²³ cm³
<h3>STEP 3 (FINDING DIAMETER OF ATOM)</h3>The atom is in a spherical shape. Hence, its Volume can be given as follows:
d = 0.355 x 10⁻⁷ cm = 3.55 x 10⁻¹⁰ m
Learn more about density here:
Answer:
A charge of -5.02 nC is uniformly distributed on a thin square sheet of nonconducting material of edge length 21.8 cm. "What is the surface charge density of the sheet"?
Explanation:
Surface charge density is a measure of how much electric charge is accumulated over a surface. It can be calculated as the charge per unit area.
We will convert all parameters in SI units.
Charge = Q = -5.02nC
Q = -5.02×C
As it is clear from question that Sheet is a square (All sides will be of equal length)
Area = A = (21.8×m) (21.8×
m) = 4.75×
m²
A = 4.75×m²
Surface charge density = Q/A
Surface charge density = (-5.02×C)/(4.75×
m²)
Surface charge density = -1.057× C
Answer:
0.72 Hz minimum frequency
Explanation:
When the damping is negligible,Amplitude is given as
here = (6.30)/(0.135) = 46.67 N/m kg
= 1.70/(0.135)(0.480) = 26.2 N/m kg
From the above equation , rearranging for ω,
⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47
⇒ ω = 8.53 or 4.52 rad/s
Frequency = f
ω=2 π f
⇒ f = ω / 2π = 8.53 /6.28 or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz
The lower frequency is 0.72 Hz and higher is 1.36 Hz