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Ber [7]
3 years ago
14

If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = –9.8 meters/sec

ond2
Physics
1 answer:
xxMikexx [17]3 years ago
8 0
The distance covered by an object starting from rest
and accelerating uniformly is . . .

                     Distance  =  (1/2 of acceleration) x (time)²

                                       = (1/2 · 9.8 m/s²)  x  (3.5 s)²

                                       =      (4.9 m/s²)  x  (3.5 s)²

                                        =      (4.9 m/s²)  x  (12.25 s²)

                                       =        (4.9 x 12.25)   meters

                                       =            60.025  meters 
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garri49 [273]

Answer:

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3 0
3 years ago
Electromagnetic induction means that moving a magnet through a loop of wire creates an electric current.
MAVERICK [17]
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4 0
4 years ago
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A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para
Firlakuza [10]

Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e   Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

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The work done by the father is 20 Joules(Nm).

7 0
3 years ago
A 5 kg ball takes 13.3 seconds for one revolution around the circle. What's the magnitude of the angular velocity of this motion
Tcecarenko [31]

Answer: 0.47 rad/sec

Explanation:

By definition, the angular velocity is the rate of change of the angle traveled with time, so we can state the following:

ω = ∆θ/ ∆t

Now, we are told that in 13.3 sec, the ball completes one revolution around the circle, which means that, by definition of angle, it has rotated 2 π rad (an arc of 2πr over the radius r), so we can find ω as follows:

ω = 2 π / 13.3 rad/sec = 0.47 rad/sec

6 0
3 years ago
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