Answer:
Bile helps in the digestion of fats
Answer:
The heat capacity of a sample is 37.7 J/K.
Explanation:
Given that,
Submerged temperature of tissue sample = 275 K
Mass of liquid nitrogen= 2 kg
Temperature = 70 K
Final temperature = 75 K
We need to calculate the heat
Using formula of heat
![Q=mc(T_{f}-T_{i})](https://tex.z-dn.net/?f=Q%3Dmc%28T_%7Bf%7D-T_%7Bi%7D%29)
Put the value into the formula
![Q=2\times1.039\times10^{3}\times(75-70)](https://tex.z-dn.net/?f=Q%3D2%5Ctimes1.039%5Ctimes10%5E%7B3%7D%5Ctimes%2875-70%29)
![Q=10390\ J](https://tex.z-dn.net/?f=Q%3D10390%5C%20J)
We need to calculate the heat capacity of a sample
Using formula of heat capacity
![\Delta S=\dfrac{Q}{T}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cdfrac%7BQ%7D%7BT%7D)
Put the value into the formula
![\Delta S=\dfrac{10390}{275}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cdfrac%7B10390%7D%7B275%7D)
![\Delta S=37.7\ J/K](https://tex.z-dn.net/?f=%5CDelta%20S%3D37.7%5C%20J%2FK)
Hence, The heat capacity of a sample is 37.7 J/K.
Explanation:
In the given question, the two metal spheres were hanged with the nylon thread.
When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.
The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.
During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.
It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.
Answer: the correct option is D (17m).
Explanation: The farthest distance at which a typical "nearsighted" frog can see clearly in air is 17m.
Answer:
The answer is 49m/s.
Explanation:
Given,
acceleration (a) =9.8m/s^2
initial velocity (u)=0 (as it was in rest condition in helicopter)
time (t) =5 s
now, final velocity (v) after 5s =?
we have,
![a = \frac{v - u}{t}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bv%20-%20u%7D%7Bt%7D%20)
![or \: 9.8 = \frac{v - 0}{5}](https://tex.z-dn.net/?f=or%20%5C%3A%209.8%20%3D%20%20%5Cfrac%7Bv%20-%200%7D%7B5%7D%20)
or, v = 49m/s
Therefore, the velocity after 5s is 49m/s.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>