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dmitriy555 [2]
3 years ago
5

Help me

Physics
1 answer:
mezya [45]3 years ago
4 0
Choose answer C.....
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two charges experience exert a force of 1n on each other when they are 1m apart. what force will these charges experience if the
Kisachek [45]

The force experienced by the charges when they are placed 2 m apart will be 0.25 N.

The force between two charges is given by Coulomb’s Law.

According to this law, the force between two charges varies inversely as the square of the distance between the charges and is directly proportional to the product of the magnitude of the two charges.

The above statement is represented by the following equation,

F= K Q1 x Q2/r^2

Here, F = Force between the two charges

K = Constant

Q1 and Q2 =  Magnitude of the two charges

r = Separation between the two charges

According to this equation, the force is inversely proportional to the square of the distance between two charges.

Initially, when the two charges are 1 m apart, the force is 1 N.

When the distance between the two charges is doubled,

then according to Coulomb’s Law, the force should decrease by 4 times.

Hence, if the charges are placed 2 meters apart,  the force becomes 1/4= 0.25 N.

To know more about "Coulomb's Law", refer to the following link:

brainly.com/question/9261306?referrer=searchResults

#SPJ4

8 0
1 year ago
(SCIENCE) 22 POINTS AND CROWN ASAP
gayaneshka [121]

Answer:

A or D

Explanation:

Net force includes addition or subtraction.

5 0
3 years ago
What is the frequency of a wave with a period of 8s?
PSYCHO15rus [73]
I don’t know the answer
3 0
2 years ago
EASY BRAINLIEST PLEASE HELP!!
Soloha48 [4]

Answer:

Solution given:

frequency[f]=x

velocity[V]=15000m/s

wave length=59m

we have

wave length=\frac{V}{f}

59m=\frac{15000}{x}

x=\frac{15000}{59}=254.Hz

frequency=254Hz

7 0
2 years ago
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Hola puntos gratis !!!!!!!!!!!!!!!!!
mina [271]

Answer:

gracias

Explanation:

7 0
3 years ago
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