Answer:
5.43 x 10^-3 Nm
Explanation:
N = 52.5, radius, r = 5.35 cm = 0.0535 m, B = 0.455 T, I = 25.3 mA = 0.0253 A
Torque = N I A B Sin theta
Here, theta = 90 degree
Torque = 52.5 x 0.0253 x 3.14 x 0.0535 x 0.0535 x 0.455
Torque = 5.43 x 10^-3 Nm
Power = 
Delilah: 170J/30s = 5.66 W
Adam: 260J/20s = 13 W
Answer:
The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Explanation:
Suppose we find the coefficient of friction and the acceleration of the 100 kg block during the time that the 60 kg block remains in contact.
Given that,
Mass of block = 60 kg
Acceleration = 2.0 m/s²
Mass = 100 kg
Horizontal force = 340 N
Let the frictional force be f.
We need to calculate the frictional force
Using balance equation

Put the value into the formula



We need to calculate the coefficient of friction
Using formula of friction force




We need to calculate the acceleration of the 100 kg block
Using formula of newton's law




Hence, The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Answer:
1.869 hours
Explanation:
= Time period = 11.1 h
Angular frequency is given by

The distance moved from highest to lowest level is given by

At the ocean surface 

= Phase constant = 0 as clock is started at 

The time taken for the water to fall the distance is 1.869 hours
To determine the amplitude of a wave, you would need to know the : B. Maximum displacement of the wave from the equilibrium position
You can find out the displacement by counting the waves that is
written on the Graph
Hope this helps